40 lines
808 B
Ruby
40 lines
808 B
Ruby
#Given a matrix(2D array),print all of its elements in spiral order.
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#e.g. [[1,2,3].[4,,5,6],[7,8,9]] => 1 2 3 6 9 8 7 4 5
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def spiralOrder(a)
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n=a.length
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m=a[0].length
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t=0
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b=m-1
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r=n-1
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l=0
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dir=0
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while t<=b && l<=r
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if dir==0
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for i in l..r
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print "#{a[t][i]} "
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end
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t+=1
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dir=1
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elsif dir==1
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for i in t..b
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print "#{a[i][r]} "
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end
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r-=1
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dir=2
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elsif dir==2
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for i in r.downto(l)
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print "#{a[b][i]} "
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end
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b-=1
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dir=3
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else
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for i in b.downto(t)
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print "#{a[i][l]} "
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end
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l+=1
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dir=0
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end
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end
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end
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