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59 lines
2.1 KiB
C++

/*This is a C++ Program to implement LCS. The longest common subsequence (LCS) problem is to find the longest subsequence common to all sequences in a set of sequences (often just two). (Note that a subsequence is different from a substring, for the terms of the former need not be consecutive terms of the original sequence.) It is a classic computer science problem, the basis of data comparison programs such as the diff utility, and has applications in bioinformatics.*/
#include <iostream>
#include <string.h>
#include <stdio.h>
using namespace std;
#define ARRAY_SIZE(A) sizeof(A)/sizeof(A[0])
// Binary search (note boundaries in the caller)
// A[] is ceilIndex in the caller
int CeilIndex(int A[], int l, int r, int key)
{
int m;
while (r - l > 1)
{
m = l + (r - l) / 2;
(A[m] >= key ? r : l) = m; // ternary expression returns an l-value
}
return r;
}
int LongestIncreasingSubsequenceLength(int A[], int size)
{
// Add boundary case, when array size is one
int *tailTable = new int[size];
int len; // always points empty slot
memset(tailTable, 0, sizeof(tailTable[0]) * size);
tailTable[0] = A[0];
len = 1;
for (int i = 1; i < size; i++)
{
if (A[i] < tailTable[0])
// new smallest value
tailTable[0] = A[i];
else if (A[i] > tailTable[len - 1])
// A[i] wants to extend largest subsequence
tailTable[len++] = A[i];
else
// A[i] wants to be current end candidate of an existing subsequence
// It will replace ceil value in tailTable
tailTable[CeilIndex(tailTable, -1, len - 1, A[i])] = A[i];
}
delete[] tailTable;
return len;
}
int main()
{
int A[] = { 2, 5, 3, 7, 11, 8, 10, 13, 6 };
int n = ARRAY_SIZE(A);
printf("Length of Longest Increasing Subsequence is %d\n",
LongestIncreasingSubsequenceLength(A, n));
return 0;
}
/*
Length of Longest Increasing Subsequence is 6