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80 lines
2.2 KiB
C++
80 lines
2.2 KiB
C++
#include<iostream>
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#include<conio.h>
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using namespace std;
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int main(void)
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{
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float a[10][10], b[10], x[10], y[10];
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int n = 0, m = 0, i = 0, j = 0;
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cout << "Enter size of 2d array(Square matrix) : ";
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cin >> n;
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for (i = 0; i < n; i++)
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{
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for (j = 0; j < n; j++)
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{
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cout << "Enter values no :(" << i << ", " << j << ") ";
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cin >> a[i][j];
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}
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}
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cout << "\nEnter Values to the right side of equation\n";
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for (i = 0; i < n; i++)
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{
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cout << "Enter values no :(" << i << ", " << j << ") ";
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cin >> b[i];
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}
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cout << "Enter initial values of x\n";
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for (i = 0; i < n; i++)
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{
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cout << "Enter values no. :(" << i<<"):";
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cin >> x[i];
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}
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cout << "\nEnter the no. of iteration : ";
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cin >> m;
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while (m > 0)
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{
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for (i = 0; i < n; i++)
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{
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y[i] = (b[i] / a[i][i]);
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for (j = 0; j < n; j++)
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{
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if (j == i)
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continue;
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y[i] = y[i] - ((a[i][j] / a[i][i]) * x[j]);
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x[i] = y[i];
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}
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printf("x%d = %f ", i + 1, y[i]);
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}
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cout << "\n";
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m--;
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}
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return 0;
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}
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/*
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Enter size of 2d array(Square matrix) : 3
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Enter values no :(0, 0) 2
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Enter values no :(0, 1) 3
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Enter values no :(0, 2) 1
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Enter values no :(1, 0) 5
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Enter values no :(1, 1) 4
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Enter values no :(1, 2) 6
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Enter values no :(2, 0) 8
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Enter values no :(2, 1) 7
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Enter values no :(2, 2) 9
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Enter Values to the right side of equation
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Enter values no :(0, 3) 2
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Enter values no :(1, 3) 3
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Enter values no :(2, 3) 4
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Enter initial values of x
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Enter values no. :(0): 0
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Enter values no. :(1): 0
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Enter values no. :(2): 0
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Enter the no. of iteration : 4
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x1 = 1.000000 x2 = -0.500000 x3 = -0.055556
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x1 = 1.777778 x2 = -1.388889 x3 = -0.055556
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x1 = 3.111111 x2 = -3.055555 x3 = 0.055555
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x1 = 5.555555 x2 = -6.277777 x3 = 0.388889
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