58 lines
1.5 KiB
Plaintext
58 lines
1.5 KiB
Plaintext
function mBreakupWordsLongerThanMax(byval vstrSentence, byval vlngMaxWordLength)
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Dim lngIndex,strNextWord,strOutput
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Dim arrWords
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lngIndex=0
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'get words into array
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arrWords=split(vstrSentence," ")
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'go through words
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strOutput=""
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'Response.Write "UBound(arrWords)" & UBo
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'
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' und(arrWords)
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For lngIndex = 0 To UBound(arrWords)
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strNextWord=arrWords(lngIndex)
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'check if > max
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if len(strNextWord > vlngMaxWordLength) Then
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'> max
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strOutput=strOutput & mSplitWord(strNextWord,vlngMaxWordLength)
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Else
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'<= max
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strOutput=strOutput & strNextWord
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End if
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Next
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'set return
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if right(strOutput,1)=" " Then
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'get rid of rightmost space
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mBreakupWordsLongerThanMax=mid(strOutput,1,len(strOutput)-1)
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Else
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'return all
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mBreakupWordsLongerThanMax=strOutput
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End if
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End function
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function mSplitWord(byval vstrWord, _
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byval vlngLength)
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'*********************************
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'purpose:split word
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'inputs: vstrWord--word to split
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' vlngLength--length to split at
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'*********************************
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Dim strOutput,lngIndex
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strOutput=""
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For lngIndex = 1 To len(vstrWord) step vlngLength
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strOutput=strOutput & _
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" " & mid(vstrWord,lngIndex,vlngLength)
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Next
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'set return
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mSplitWord= mid(strOutput,2) & " "
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End function |