programming-examples/js/Conditional/Write a JavaScript for loop that will iterate from 0 to 15. For each iteration, it will check if the current number is odd or even, and display a message to the screen..js

for (var x=0; x<=15; x++) {  
        if (x === 0) {  
                console.log(x +  " is even");  
        }  
        else if (x % 2 === 0) {  
                console.log(x + " is even");     
        }  
        else {  
                console.log(x + " is odd");  
        }  
}