programming-examples/java/Numerical_Problems/Java Program to Implement Cubic convergence 1(Divide)pi Algorithm.java
2019-11-15 12:59:38 +01:00

47 lines
1.4 KiB
Java

/*
This is a Java Program to Implement Cubic convergence 1/pi Algorithm. Cubic convergence is an algorithm used to calculate the value of 1/p.
*/
/**
** Java Program to Implement Cubic convergence 1/pi Algorithm
**/
import java.util.Scanner;
/** Class CubicConvergencePi **/
public class CubicConvergencePi
{
/** compute 1/pi **/
public double getOneByPi(int k)
{
double ak = 1.0/3.0;
double sk = (Math.sqrt(3) - 1)/2;
double ak1, sk1, rk1;
for (int i = 0; i < k; i++)
{
rk1 = 3.0 / (1 + 2 * Math.pow((1 - sk * sk * sk), (1.0/3.0)));
sk1 = (rk1 - 1)/2.0;
ak1 = rk1 * rk1 * ak - Math.pow(3, i) * (rk1 * rk1 - 1);
ak = ak1;
sk = sk1;
}
return ak;
}
/** Main function **/
public static void main (String[] args)
{
Scanner scan = new Scanner(System.in);
System.out.println("Cubic Convergence 1/Pi Algorithm Test\n");
/** Make an object of CubicConvergence class **/
CubicConvergencePi cc = new CubicConvergencePi ();
System.out.println("Enter number of iterations");
int k = scan.nextInt();
System.out.println("\nValue of 1/pi : "+ cc.getOneByPi(k));
}
}
/*
Enter number of iterations
3
Value of 1/pi : 0.3183098861837896