programming-examples/c/Series_Programs/C Program to find (1!(by)1) + (2!(by)2) + (3!(by)3) + (4!(by)4) + (5!(by)5) + ...c

/*(1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n)*/
#include<stdio.h>
long fact(int n)
{
    long i, f=1;
    for(i=1; i<=n; i++)
        {
            f=f*i;
        }
    return f;
}

int main()
{
    long i,n;
    double sum=0;
    printf("Enter value of n ");
    scanf("%d",&n);
    for(i=1; i<=n; i++)
        {
            sum=sum+(fact(i)/i);
        }
    printf("Sum: %lf",sum);
    return 0;
}