programming-examples/ruby/Algorithms/merge_sort_bu.rb
2019-11-15 12:59:38 +01:00

90 lines
1.7 KiB
Ruby

# Bottom-up mergesort of a lined list without an auxiliary space,
# see test/merge_sort_bu_test.rb
class MergeSortBu
Node = Struct.new(:value, :next)
def sort(list)
return list if list.nil? || list.next.nil?
size = 1
result = list
loop do
merges = 0
first = result
prev_last = nil
while first
second = find_second(first, size)
break if first == second
head, last = merge(first, second, size)
prev_last.next = head if prev_last
prev_last = last
first = last.next
result = head if merges == 0
merges += 1
end
return result if merges == 1 && last.next.nil?
size *= 2
end
end
private
def merge(first, second, size)
fsize = size
ssize = size
head = nil
tail = nil
next_first = nil
while (fsize != 0) || (second && ssize != 0)
if ssize == 1 && next_first.nil?
next_first = second.next
end
if fsize == 0
tail = link(tail, second)
second = second.next
ssize -= 1
elsif second.nil? || ssize == 0
tail = link(tail, first)
first = first.next
fsize -= 1
elsif first.value > second.value
tail = link(tail, second)
second = second.next
ssize -= 1
else
tail = link(tail, first)
first = first.next
fsize -= 1
end
head = tail if head.nil?
end
tail.next = next_first
[head, tail]
end
def link(tail, node)
tail.next = node if tail
node
end
def find_second(first, size)
second = first
size.times do
break if second.next.nil?
second = second.next
end
second
end
end