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Java

/*This is a Java Program to find the area of a polygon using slicker method. The algorithm assumes the usual mathematical convention that positive y points upwards. In computer systems where positive y is downwards (most of them) the easiest thing to do is list the vertices counter-clockwise using the “positive y down” coordinates. The two effects then cancel out to produce a positive area.*/
//This is a java program to find the area of polygon using Slicker algorithm
import java.util.*;
class Area_polygon_Slicker
{
static final int MAXPOLY = 200;
static final double EPSILON = 0.000001;
static class Point
{
double x, y;
}
static class Polygon
{
Point p[] = new Point[MAXPOLY];
int n;
Polygon()
{
for (int i = 0; i < MAXPOLY; i++)
p[i] = new Point();
}
}
static double area(Polygon p)
{
double total = 0;
for (int i = 0; i < p.n; i++)
{
int j = (i + 1) % p.n;
total += (p.p[i].x * p.p[j].y) - (p.p[j].x * p.p[i].y);
}
return total / 2;
}
static public void main(String[] args)
{
Polygon p = new Polygon();
Scanner sc = new Scanner(System.in);
System.out.println("Enter the number of points in Polygon: ");
p.n = sc.nextInt();
System.out.println("Enter the coordinates of each point: <x> <y>");
for (int i = 0; i < p.n; i++)
{
p.p[i].x = sc.nextDouble();
p.p[i].y = sc.nextDouble();
}
double area = area(p);
if (area > 0)
System.out.print("The Area of Polygon with " + p.n
+ " points using Slicker Algorithm is : " + area);
else
System.out.print("The Area of Polygon with " + p.n
+ " points using Slicker Algorithm is : " + (area * -1));
sc.close();
}
}
/*
Enter the number of points in Polygon:
4
Enter the coordinates of each point: <x> <y>
1 1
1 6
6 6
6 1
The Area of Polygon with 4 points using Slicker Algorithm is : 25.0
Enter the number of points in Polygon:
5
Enter the coordinates of each point: <x> <y>
1 2
4 5
9 8
3 2
1 5
The Area of Polygon with 5points using Slicker Algorithm is : 6.0