programming-examples/c/Series_Programs/C Program to find (1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ...c
2019-11-15 12:59:38 +01:00

25 lines
442 B
C

/*(1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)*/
#include<stdio.h>
#include<math.h>
long power(int a, int b)
{
long i, p=1;
for(i=1; i<=b; i++)
{
p=p*a;
}
return p;
}
int main()
{
long i,n,sum=0;
printf("Enter value of n");
scanf("%d",&n);
for(i=1; i<=n; i++)
{
sum=sum+power(i,i);
}
printf("Sum: %d",sum);
return 0;
}