programming-examples/c/Search_Sorting/C Program to demonstrate recursive merge sort.C
2019-11-15 12:59:38 +01:00

68 lines
1.6 KiB
C

/* Program to demonstrate recursive merge sort */
#include <stdio.h>
#include <conio.h>
void mergesort(int x[ ], int lb, int ub) ;
void merge(int x[ ], int lb1, int ub1, int ub2) ;
void show(int x[ ], int lb, int ub) ;
void main()
{
int i, n, x[20] ;
clrscr() ;
printf("Enter the number of elements: ") ;
scanf("%d",&n) ;
printf("Enter the elements:\n") ;
for(i=0 ; i<n ; i++)
scanf("%d",&x[i]) ;
mergesort(x,0,n-1) ;
printf("Sorted array is as shown:\n") ;
for(i=0 ; i<n ; i++)
printf("%d ", x[i]) ;
getch() ;
}
void mergesort(int x[ ], int lb, int ub)
{
int mid ;
if(lb<ub)
{
mid=(lb+ub)/2 ;
mergesort(x,lb,mid) ;
mergesort(x,mid+1,ub) ;
merge(x,lb,mid,ub) ;
}
}
void merge(int x[ ], int lb1, int ub1, int ub2)
{
int temp[50], i, j, k ;
i=lb1 ;
j=ub1+1 ;
k=0 ;
while(i<=ub1&&j<=ub2)
if(x[i]<x[j]) /* use > for descending order */
temp[k++]=x[i++] ;
else
temp[k++]=x[j++] ;
while(i<=ub1)
temp[k++]=x[i++] ;
while(j<=ub2)
temp[k++]=x[j++] ;
for(i=lb1, j=0 ; i<=ub2 ; i++, j++)
x[i]=temp[j] ;
show(x,lb1,ub2) ;
}
void show(int x[ ], int lb, int ub)
{
int i ;
for(i=lb ; i<=ub ; i++)
printf("%d ", x[i]) ;
printf("\n\n") ;
}
/* The method show() is optional. It is written to show output of each pass. It may not be written in theory exam. It is required only in practical exams */