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71 lines
1.4 KiB
Ruby
71 lines
1.4 KiB
Ruby
#Given two sorted arrays ,Print the elements in the union and intersection of these arrays
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#Time-complexity:O(n+m)(n=length of array1 and m=length of array2),Auxiliary-space: O(1)
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# Method for finding Union
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def union(a,b)
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len1=a.length
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len2=b.length
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ctr1=0
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ctr2=0
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puts "Union of the gives arrays:"
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while (ctr1<len1 && ctr2<len2)
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if a[ctr1]==b[ctr2]
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print "#{a[ctr1]} "
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ctr1+=1
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ctr2+=1
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elsif a[ctr1]<b[ctr2]
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print "#{a[ctr1]} "
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ctr1+=1
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else
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print "#{b[ctr2]} "
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ctr2+=1
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end
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end
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#Printing remaining elements(if any)
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while ctr1<len1
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print "#{a[ctr1]} "
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ctr1+=1
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end
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while ctr2<len2
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print "#{b[ctr2]} "
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ctr2+=1
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end
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end
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# Method for finding Intersection
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def intersection(a,b)
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len1=a.length
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len2=b.length
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ctr1=0
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ctr2=0
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puts "Intersection of the gives arrays:"
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while (ctr1<len1 && ctr2<len2)
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if a[ctr1]==b[ctr2]
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print "#{a[ctr1]} "
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ctr1+=1
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ctr2+=1
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elsif a[ctr1]<b[ctr2]
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ctr1+=1
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else
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ctr2+=1
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end
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end
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end
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#Ruby magic: One line solutions
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def union(a,b)
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print a | b # union([1,2,3],[2,3,4]) => [1, 2, 3, 4]
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end
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def intersection(a,b)
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print a & b # intersection([1,2,3],[2,3,4]) => [2, 3]
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end
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