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55 lines
1.1 KiB
Ruby

# Given a sorted array of n unique integers where each integer is in the range from 0 to m-1 and m > n.
# Find the smallest number that is missing from the array.
#Algorithm: Binary Search (Compare elements with indexes and then decide)
#Time-complexity: O(logn), Auxiliary-space: O(1)
# Iterative
def smallest_missing(a)
lo=0
hi=a.length-1
while hi>lo
mid=lo+(hi-lo)/2
if a[mid]>mid
hi=mid
else
lo=mid+1
end
end
if a[lo]==lo # if lo == end of array
print lo+1
else
print lo
end
end
smallest_missing([0, 1, 2, 3]) #=> 4
smallest_missing([0, 1, 2, 5]) #=> 3
#recursive
#Driver function
def driver_func(a)
lo=0
hi=a.length-1
print smallest_missing(a,lo,hi)
end
#Algorithm
def smallest_missing(a,lo,hi)
if lo>hi
return hi+1
end
if a[lo] != lo
return lo
end
mid= lo+(hi-lo)/2
if a[mid]>mid
return smallest_missing(a,lo,mid)
else
return smallest_missing(a,mid+1,hi)
end
end
driver_func([0, 1, 2, 3]) #=> 4
driver_func([0, 1, 2, 5]) #=> 3