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Ruby

#Given an array find maximum difference between two elements such that the karger appears after the smaller.
#Approach 1: keep track of min so far and find the diff.
#Time-complexity:O(n),Auxiliary-space:O(1)
def max_diff(a)
len=a.length
min_so_far=a[0]
diff=a[1]-a[0]
for i in 1...len
diff= a[i]-min_so_far if (a[i]-min_so_far > diff)
min_so_far=a[i] if (a[i] < min_so_far)
end
return diff
end
max_diff([100, 10, 5, 91, 1, 8, 16, 21]) # => 86
#Approach 2: find diff between adjacent elements,now find the max sum subarray of diff.
#Time-complexity:O(n),Auxiliary-space:O(1)
def max_diff(a)
len=a.length
diff=a[1]-a[0]
curr_sum=diff
max_sum=curr_sum
for i in 1...len-1
#calculate current diff
diff=a[i+1]-a[i]
#calculate current sum
if curr_sum>0
curr_sum+=diff
else
curr_sum=diff
end
#update max_sum
max_sum=curr_sum if curr_sum>max_sum
end
return max_sum
end
min_diff([100, 10, 5, 91, 1, 8, 16, 21]) # => 86