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32 lines
709 B
Ruby

# Find majority element(if exists) in a given sorted array.
# A majority element in an array A[] of size n is an element that appears more than n/2 times
#Time-complexity: O(logn), Auxiliary-space:O(1)
#Algorithm: Binary-search
def majority_element(a)
len=a.length
lo=0
hi=len-1
candidate=a[lo+(hi-lo)/2]
while hi-lo>1
mid=lo+(hi-lo)/2
if a[mid]>=candidate
hi=mid
else
lo=mid
end
end
if a[hi]==candidate
left_index=hi
right_index=left_index+(len/2)
if a[right_index]==candidate
return candidate
else
return -1
end
end
end
majority_element([1,2, 2, 3, 3, 3, 3]) # => 3