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26 lines
692 B
Ruby

#Given an array 'a',create a product array where product[i]==product of all elements except a[i]
#Time-complexity: O(n), Space-complexity: O(n),Auxiliary-space: O(1)
def product_array(a)
len=a.length
product=Array.new(len,1) # Initilaize product array elements to 1
temp=1
#Loop to store product of left elements
for i in 0...len
product[i]=temp
temp*=a[i]
end
temp=1 #reset temp variable to 1
#Loop to multiply stored left products with right products
for i in (len-1).downto(0)
product[i]*=temp
temp*=a[i]
end
return product
end
product_array([1,2,3,4,5,6]) # => [720, 360, 240, 180, 144, 120]