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53 lines
2.0 KiB
Java
53 lines
2.0 KiB
Java
/*
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To find missing numbers in an array first we need to make sure that array is sorted.
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After sorting we need to check that array each element with next element then we can find the difference.
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if Array is not sorted :To sort array use Arrays.sort(array);
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If difference is 1 then no need to do any thing because numbers are in order.
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If difference is not equal to 1 then we need to print all those numbers or pick those numbers and place it in one array.
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this would be the logic to find missing numbers in an array
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Here there may be a chance of array not starts with 1 then we need to check first itself whether array starts with 1 or not if not we need to print 1 to starting element of array.
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for example int a[]={4,5,6,8}; then we need to print 1 2 3 7.
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*/
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public class PrintMissingNumbers
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{
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private static void findMissingNumber(int[] number)
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{
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// take max length as last number in array
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int k[] = new int[number[number.length-1]];
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int m=0;
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if(number[0]!=1)
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{
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for (int x = 1; x < number[0]; x++)
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{
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k[m] = x;
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m++;
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}
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}
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for (int i = 0; i < number.length -1; i++)
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{
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int j = i+1;
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int difference = number[j] - number[i] ;
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if(difference != 1 )
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{
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for (int x = 1; x < difference; x++)
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{
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k[m] = number[i] + x;
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m++;
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}
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}
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}
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System.out.println("missing numbers in array ::");
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for (int l = 0; l < m ; l++)
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{
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System.out.println( k[l]+" ");
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}
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}
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public static void main(String[] args)
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{
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int a[]= {2,4,6,9,10,20};
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//if Array is not sorted :To sort array use ArraysC.sort(a);
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findMissingNumber(a);
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}
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} |