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54 lines
1.7 KiB
C
54 lines
1.7 KiB
C
/* Structure - Cricket
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Define a structure called cricket that will describe the following info
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1)player name 2)team name 3)no of matches played 4)batting average
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Declare an array player with 50 elements. Write a program to read information about all 50 players. Sort the information on their batting average and print the results */
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#include <stdio.h>
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#include <conio.h>
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void main()
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{
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struct cricket
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{
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char pname[20] ;
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char tname[20] ;
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int np ;
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float avg ;
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};
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/* Some compilers do not allow float member in a structure. In that case make avg to be of data type int */
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struct cricket player[50], temp ;
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int i, j ;
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clrscr();
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printf("Enter player name , team name , number of matches played and batting average for 50 players:\n") ;
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for(i=0 ; i<50 ; i++)
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scanf("%s %s %d %f", player[i].pname, player[i].tname, &player[i].np, &player[i].avg) ;
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for(i=0 ; i<50-1 ; i++)
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for(j=0 ; j<50-1-i ; j++)
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if(player[j].avg < player[j+1].avg )
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{
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temp=player[j] ;
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player[j]=player[j+1] ;
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player[j+1]=temp ;
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}
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printf("\nList in descending order of batting average is as shown:\n") ;
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for(i=0 ; i<50 ; i++)
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printf("%s %s %d %f \n", player[i].pname, player[i].tname, player[i].np, player[i].avg) ;
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getch();
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}
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/*
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The following output is shown for 3 players only:
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Enter player name , team name , number of matches played and batting average for 50 players:
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Jack Australia 202 67.5
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Sachin India 210 82.75
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Tim U.K. 205 76.25
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List in descending order of batting average is as shown:
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Sachin India 210 82.750000
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Tim U.K. 205 76.250000
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Jack Australia 202 67.500000
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*/
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