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76 lines
2.0 KiB
C
76 lines
2.0 KiB
C
/*
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* C Program to Find the Frequency of Every Word in a
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* given String
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*/
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#include <stdio.h>
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#include <string.h>
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void main()
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{
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int count = 0, c = 0, i, j = 0, k, space = 0;
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char str[100], p[50][100], str1[20], ptr1[50][100];
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char *ptr;
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printf("Enter the string\n");
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scanf(" %[^\n]s", str);
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printf("string length is %d\n", strlen(str));
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for (i = 0; i<strlen(str); i++)
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{
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if ((str[i] == ' ')||(str[i] == ', ')||(str[i] == '.'))
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{
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space++;
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}
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}
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for (i = 0, j = 0, k = 0; j < strlen(str); j++)
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{
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if ((str[j] == ' ')||(str[j] == 44)||(str[j] == 46))
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{
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p[i][k] = '\0';
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i++;
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k = 0;
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}
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else
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p[i][k++] = str[j];
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}
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k = 0;
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for (i = 0; i <= space; i++)
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{
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for (j = 0; j <= space; j++)
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{
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if (i == j)
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{
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strcpy(ptr1[k], p[i]);
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k++;
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count++;
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break;
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}
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else
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{
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if (strcmp(ptr1[j], p[i]) != 0)
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continue;
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else
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break;
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}
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}
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}
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for (i = 0; i < count; i++)
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{
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for (j = 0; j <= space; j++)
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{
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if (strcmp(ptr1[i], p[j]) == 0)
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c++;
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}
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printf("%s -> %d times\n", ptr1[i], c);
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c = 0;
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}
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}
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/*
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*OUTPUT:
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Enter the string
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welcome to sanfoundry's class, welcome to c class
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string length is 48
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welcome -> 2 times
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to -> 2 times
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sanfoundry's -> 1 times
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class -> 2 times
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c -> 1 times
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*/ |