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115 lines
3.4 KiB
C
115 lines
3.4 KiB
C
/*
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* C Program to Concatenate the given two Strings Lexically
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*/
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#include <string.h>
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#include <stdio.h>
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void sort(char *p);
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void main()
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{
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char string1[100], string2[100];
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int i, len, j;
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printf("\nEnter a string : ");
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scanf("%[^\n]s", string1);
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printf("\nEnter another string to concat : ");
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scanf(" %[^\n]s", string2);
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len = strlen(string1);
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string1[len] = ' ';
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for(i = 0, j = len + 1; i < strlen(string2); i++, j++)
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string1[j] = string2[i];
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string1[j]='\0';
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sort(string1);
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}
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/* Sorting to make concatenation lexical */
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void sort(char *p)
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{
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char temp[100];
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char a[100][100];
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int t1, i, j = 0, k = 0, l = strlen(p), x = 0, y = 0, z = 0, count, l1, l2;
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for (i = 0; i < l; i++)
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{
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if (p[i] != ' ')
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{
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a[k][j++] = p[i];
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}
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else
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{
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a[k][j] = '\0';
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k++;
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j = 0;
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}
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}
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t1 = k;
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k = 0;
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for (i = 0; i < t1; i++)
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{
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for (j = i + 1; j <= t1; j++)
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{
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l1 = strlen(a[i]);
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l2 = strlen(a[j]);
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if (l1 > l2)
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count = l1;
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else
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count = l2;
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x = 0, y = 0;
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while ((x < count) || (y < count))
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{
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if (a[i][x] == a[j][y])
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{
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x++;
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y++;
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continue;
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}
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else if (a[i][x] < a[j][y]) break;
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else if (a[i][x] > a[j][y])
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{
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for (z = 0; z < l2; z++)
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{
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temp[z] = a[j][z];
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a[j][z] = '\0';
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}
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temp[z] = '\0';
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for (z = 0; z < l1; z++)
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{
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a[j][z] = a[i][z];
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a[i][z] = '\0';
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}
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a[j][z] = '\0';
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for (z = 0; z < strlen(temp); z++)
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{
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a[i][z] = temp[z];
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}
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break;
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}
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}
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}
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}
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for (i = 0; i < l; i++)
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p[i] = '\0';
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k = 0;
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j = 0;
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for (i = 0; i < l; i++)
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{
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if (a[k][j] != '\0')
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{
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p[i] = a[k][j++];
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}
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else
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{
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k++;
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j = 0;
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p[i] = ' ';
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}
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}
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puts(p);
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}
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/*
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*OUTPUT:
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Enter a string : hello this
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Enter another string to concat : is sanfoundry
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hello is sanfoundry this
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*/ |