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45 lines
1.4 KiB
C

/* Perfect Square - Program to find four digit perfect squares, where the number represented by the first two digits and the number represented by the last two digits are also perfect squares. */
/* For eg 1681=41^2 16=4^2 81=9^2 */
#include <stdio.h>
#include <conio.h>
#include <math.h>
void main()
{
int n, n1, n2, i, flag1, flag2, flag3 ;
clrscr() ;
printf("Four digit perfect squares with required property are as shown:\n");
for(n=1000 ; n<=9999 ; n++)
{
n1=n%100 ; /*Extracting last two digits*/
n2=n/100 ; /*Extracting first two digits*/
/*Checking whether the first two digits are perfect squares*/
flag1=0 ;
i=sqrt(n2) ; /* Remember i is integer whereas sqrt() returns double */
if(n2==i*i)
flag1=1 ;
/*Checking whether the last two digits are perfect squares*/
flag2=0 ;
i=sqrt(n1) ;
if(n1==i*i)
flag2=1 ;
/*Checking whether the number itself is a perfect square*/
flag3=0 ;
i=sqrt(n) ;
if(n==i*i)
flag3=1 ;
if(flag1==1 && flag2 ==1 && flag3==1)
printf("%d ", n) ;
}
getch() ;
}
/*
Output
Four digit perfect squares with required property are as shown:
1600 1681 2500 3600 4900 6400 8100
*/