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108 lines
2.2 KiB
C
108 lines
2.2 KiB
C
/* Matrix transpose - Program to find transpose of a matrix m*n using functions to
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1) Read elements of matrix
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2) find transpose
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3) Display elements of matrix
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4) find transpose using single matrix.
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May 2013 */
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#include <stdio.h>
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#include <conio.h>
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void read(int x[ ][10], int nr, int nc) ;
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void transpose(int x[ ][10], int y[ ][10], int nr, int nc) ;
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void show(int y[ ][10], int nr, int nc) ;
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void singletranspose(int x[ ][10], int nr, int nc) ;
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void main()
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{
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int x[10][10], y[10][10], m, n ;
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clrscr();
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printf("Enter the number of rows and columns: ");
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scanf("%d %d", &m, &n) ;
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printf("Enter elements of the matrix row-wise:\n") ;
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read(x, m, n) ;
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transpose(x, y, m, n) ;
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printf("Transpose of given matrix is:\n") ;
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show(y,n,m) ;
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if(m==n)
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{
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singletranspose(x,m,n);
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printf("Transpose using single matrix is:\n");
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show(x,n,m);
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}
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else
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printf("The matrix is not a square matrix");
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getch();
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}
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void read(int x[ ][10], int nr, int nc)
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{
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int r, c ;
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for(r=0 ; r<nr ; r++)
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for(c=0 ; c<nc ; c++)
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scanf("%d", &x[r][c]) ;
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}
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void transpose(int x[ ][10], int y[ ][10], int nr, int nc)
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{
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int r, c ;
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for(r=0 ; r<nr ; r++)
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for(c=0 ; c<nc ; c++)
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y[c][r]=x[r][c] ;
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}
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void singletranspose(int x[ ][10], int nr, int nc)
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{
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int r, c, t ;
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for(r=0 ; r<nr ; r++)
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for(c=0 ; c<nc ; c++)
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if(r<c)
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{
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t=x[r][c];
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x[r][c]=x[c][r];
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x[c][r]=t;
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}
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}
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void show(int y[ ][10], int nr, int nc)
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{
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int r, c ;
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for(r=0 ; r<nr ; r++)
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{
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for(c=0 ; c<nc ; c++)
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printf("%d ", y[r][c]) ;
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printf("\n") ;
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}
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}
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/*
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Output1:
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Enter the number of rows and columns: 3 3
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Enter elements of the matrix:
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11 2 4
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3 22 6
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5 7 44
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Transpose of given matrix is:
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11 3 5
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2 22 7
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4 6 44
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Transpose using single matrix is:
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11 3 5
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2 22 7
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4 6 44
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Output2:
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Enter the number of rows and columns: 2 3
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Enter elements of the matrix:
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2 4 6
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3 5 7
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Transpose of given matrix is:
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2 3
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4 5
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6 7
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The matrix is not a square matrix
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*/
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