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72 lines
2.1 KiB
C#

/*
* C# Program to Find the Standard Deviation of a Set of Given Numbers
*/
using System;
using System.Collections.Generic;
namespace SampleApp
{
internal class Program
{
private static void Main()
{
List<double> number = new List<double> { 1, 2, 3, 4, 5, 6 };
double mean = number.Mean();
double variance = number.Variance();
double sd = number.StandardDeviation();
Console.WriteLine("Mean: {0} , Variance: {1} , SD: {2} ", mean, variance, sd);
Console.ReadKey();
}
}
public static class list
{
public static double Mean(this List<double> values)
{
return values.Count == 0 ? 0 : values.Mean(0, values.Count);
}
public static double Mean(this List<double> values, int start, int end)
{
double s = 0;
for (int i = start; i < end; i++)
{
s += values[i];
}
return s / (end - start);
}
public static double Variance(this List<double> values)
{
return values.Variance(values.Mean(), 0, values.Count);
}
public static double Variance(this List<double> values, double mean)
{
return values.Variance(mean, 0, values.Count);
}
public static double Variance(this List<double> values, double mean, int start, int end)
{
double variance = 0;
for (int i = start; i < end; i++)
{
variance += Math.Pow((values[i] - mean), 2);
}
int n = end - start;
if (start > 0) n -= 1;
return variance / (n);
}
public static double StandardDeviation(this List<double> values)
{
return values.Count == 0 ? 0 : values.StandardDeviation(0, values.Count);
}
public static double StandardDeviation(this List<double> values, int start, int end)
{
double mean = values.Mean(start, end);
double variance = values.Variance(mean, start, end);
return Math.Sqrt(variance);
}
}
}
/*
Mean : 3.5 Variance : 2.916666666667 S.D = 1.7078251256993