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138 lines
1.7 KiB
C++

Find shortest path using floyd warshall algorithm
Code :
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
#include<stdlib.h>
class path
{
int n;
int p[10][10];
int a[10][10];
int c[10][10];
public:
void get();
void pm();
void ap();
void disp();
};
void path::get()
{
int i,j,k;
clrscr();
cout<<"Enter the no. of nodes in the graph :";
cin>>n;
cout<<"
Enter the adjacency matrix :
";
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
// cout<<"a["<<i<<","<<j<<"] = ";
cin>>a[i][j];
p[i][j]=0;
}
}
cout<<"
Enter The cost matrix is :
";
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
// cout<<"a["<<i<<","<<j<<"] = ";
cin>>c[i][j];
}
}
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
p[i][j]=a[i][j];
}
}
}
void path::disp()
{
// cout<<"
The output matrix for the given graph is :
";
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
cout<<p[i][j]<< " ";
}
cout<<endl;
}
}
void path::pm()
{
int i,j,k;
for(k=1;k<=n;k++)
{
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
p[i][j]=p[i][j] || p[i][k] && p[k][j];
}
}
}
}
void path::ap()
{
int i,j,k;
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
p[i][j]=c[i][j];
}
}
for(k=1;k<=n;k++)
{
for(i=1;i<=n;i++)
{
for(j=1;j<=n;j++)
{
if(p[i][j]<p[i][k]+p[k][j])
{
p[i][j]=p[i][j];
}
else
{
p[i][j]=p[i][k]+p[k][j];
}
}
}
}
}
void main()
{
path p;
p.get();
p.pm();
cout<<"path matrix is :
";
p.disp();
getch();
p.ap();
cout<<"all pair shortest path matrix is :
";
p.disp();
getch();
}