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66 lines
2.0 KiB
C++

/*-------------- BACKWARD DIFFERENCES GENERATION FOR INTERPOLATION ----*/
/* THE PROGRAM GENERATES A BACKWARD DIFFERENCES TABLE FROM GIVEN
DATA. THE VALUES OF x AND CORRESPONDING y = f(x) ARE TO BE
ENTERED IN THE ARRAY FORMAT.
INPUTS : 1) Number of entries of the data.
2) Values of 'x' & corresponding y = f(x).
OUTPUTS : Backward difference table array. */
/*------------------------------ PROGRAM --------------------------*/
#include<stdio.h>
#include<math.h>
#include<stdlib.h>
#include<conio.h>
void main()
{
double y[20][20],x[20];
/* ARRAY OF N*N ELEMENTS FOR BACKWARD DIFFERENCE TABLE */
int i,j,k,n;
clrscr();
printf("\n\tBACKWARD DIFFERENCES GENERATION FOR INTERPOLATION");
printf("\n\n The form of equation is y = f(x)\n");
printf("\n\nEnter the number of entries (max 20) = ");
scanf("%d",&n); /* ENTER NUMBER OF ENTRIES IN THE TABLE */
for(i = 0; i < n; i++)
{
/* LOOP TO GET x AND y = f(x) IN THE TABLE */
printf("x%d = ",i);
scanf("%lf",&x[i]);
printf(" y%d = ",i);
scanf("%lf",&y[i][0]);
}
k = 0;
for(j = 1; j < n; j++)
{
/* LOOP TO CALCULATE BACKWARD DIFFERENCES */
k++;
for(i = n-1; i >= k; i--)
{
y[i][j] = y[i][j-1] - y[i-1][j-1];
}
}
k = n ;
clrscr();
printf("\n The backward difference table is as follows . . .\n");
printf("\n\tx\ty\tDy\tD2y\tD3y\tD4y\tD5y\tD6y\n");
for(i = 0; i < n; i++)
{
/* LOOP TO PRINT BACKWARD DIFFERENCES */
printf("\nx%d = %4.2lf",i,x[i]);
for(j = 0; j < i+1; j++)
{
printf("\t%4.2lf ",y[i][j]);
}
printf("\n");
}
}
/*------------------------------End of program-------------------------*/