name free page 60,132 title 'FREE --- Report free space on disk' ; FREE --- a utility to report free space on ; the default or selected disk drive. ; ; Requires PC-DOS or MS-DOS 2.0. ; ; Used in the form: ; A> FREE [unit:] ; (item in square brackets is optional) ; cr equ 0dh ;ASCII carriage return lf equ 0ah ;ASCII line feed blank equ 20h ;ASCII space code eom equ '$' ;end of string marker ; Here we define a dummy segment containing labels ; for the default file control block and the command tail buffer, ; so that the main program can access those locations. ; psp segment para public 'PSP' org 05ch fcb label byte ;default file control block org 080h command label byte ;default command buffer psp ends cseg segment para public 'CODE' assume cs:cseg,ds:psp,es:data,ss:stack get_drive proc near ;get drive selection, if any, ;otherwise obtain the identity ;of the current disk drive. ;Return drive (1=A, 2=B, etc) in AL. ; mov al,fcb ;Pick up the drive code, parsed ;by DOS into the default file ;control block. or al,al ;Is it the default? jnz get_drive1 ;no, use it mov ah,19h ;Yes, get the actual current int 21h ;drive from PC-DOS. inc al ;Increment to match FCB code. get_drive1: ;Return drive code in AL. ret get_drive endp free proc far ;entry point from PC-DOS push ds ;save DS:0000 for final xor ax,ax ;return to PC-DOS push ax mov ax,data ;make our data segment mov es,ax ;addressable via ES register. mov ah,30h ;check version of PC-DOS. int 21h cmp al,2 jae free1 ;proceed, DOS 2.0 or greater. mov dx,offset msg2 ;DOS 1.x --- print error message mov ax,es ;and exit. First fix up DS register mov ds,ax ;so error message is addressable. jmp free4 free1: call get_drive ;get drive selection into DL. push es ;copy ES to DS for remainder pop ds ;of the program... assume ds:data ;and tell assembler about it. mov dl,al add al,'A'-1 ;form drive letter from drive code, mov outputb,al ;and put it into the output string. mov ah,36h ;now call DOS to get free disk space. int 21h cmp ax,-1 ;was drive invalid? je free3 ;yes,go print error message ;drive was ok, so now registers are... ;AX=number of sectors per cluster ;BX=available clusters, ;CX=number of bytes per sector, ;DX=total clusters per drive. ;calculate free space: mul cx ;sectors per cluster * bytes per sector ;(we assume this won't overflow into DX) mul bx ;then * available clusters ;DX:AX now contains free space in bytes. ;SI = last byte address for converted string. mov si,offset (outputa+9) mov cx,10 ;CX = 10, radix for conversion call bin_to_asc ;convert free space value to ASCII, mov dx,offset output jmp free4 ;and print it out. free3: mov dx,offset msg1 ;illegal drive, print error free4: mov ah,9 ;print the string whose address int 21h ;is in DX. ret ;then return to DOS. free endp ; Convert 32 bit binary value to ASCII string. ; ; Call with DX:AX = signed 32 bit value ; CX = radix ; SI = last byte of area to store resulting string ; (make sure enough room is available to store ; the string in the radix you have selected.) ; ; Destroys AX, BX, CX, DX, and SI. ; bin_to_asc proc near ;convert DX:AX to ASCII. ;force storage of at least 1 digit. mov byte ptr [si],'0' or dx,dx ;test sign of 32 bit value, pushf ;and save sign on stack. jns bin1 ;jump if it was positive. not dx ;it was negative, take 2's complement not ax ;of the value. add ax,1 adc dx,0 bin1: ;divide the 32 bit value by the radix ;to extract the next digit for the ;forming string. mov bx,ax ;is the value zero yet? or bx,dx jz bin3 ;yes, we are done converting. call divide ;no, divide by radix. add bl,'0' ;convert the remainder to an ASCII digit. cmp bl,'9' ;we might be converting to hex ASCII, jle bin2 ;jump if in range 0-9, add bl,'A'-'9'-1 ;correct it if in range A-F. bin2: mov [si],bl ;store this character into string. dec si ;back up through string, jmp bin1 ;and do it again. bin3: ;restore sign flag, popf ;was original value negative? jns bin4 ;no, jump ;yes,store sign into output string. mov byte ptr [si],'-' bin4: ret ;back to caller. bin_to_asc endp ; General purpose 32 bit by 16 bit unsigned divide. ; This must be used instead of the plain machine unsigned divide ; for cases where the quotient may overflow 16 bits (for example, ; dividing 100,000 by 2). If called with a zero divisor, this ; routine returns the dividend unchanged and gives no warning. ; ; Call with DX:AX = 32 bit dividend ; CX = divisor ; ; Returns DX:AX = quotient ; BX = remainder ; CX = divisor (unchanged) ; divide proc near ; Divide DX:AX by CX jcxz div1 ; exit if divide by zero push ax ; 0:dividend_upper/divisor mov ax,dx xor dx,dx div cx mov bx,ax ; BX = quotient1 pop ax ; remainder1:dividend_lower/divisor div cx xchg bx,dx ; DX:AX = quotient1:quotient2 div1: ret ; BX = remainder2 divide endp cseg ends data segment para public 'DATA' output db cr,lf outputa db 10 dup (blank) db ' bytes free on drive ' outputb db 'x:',cr,lf,eom msg1 db cr,lf db 'That disk drive does not exist.' db cr,lf,eom msg2 db cr,lf db 'Requires DOS version 2 or greater.' db cr,lf,eom data ends stack segment para stack 'STACK' db 64 dup (?) stack ends end free