/*This is a java program to find topological sort of DAG. In computer science, a topological sort (sometimes abbreviated topsort or toposort) or topological ordering of a directed graph is a linear ordering of its vertices such that for every directed edge uv from vertex u to vertex v, u comes before v in the ordering. For instance, the vertices of the graph may represent tasks to be performed, and the edges may represent constraints that one task must be performed before another; in this application, a topological ordering is just a valid sequence for the tasks. A topological ordering is possible if and only if the graph has no directed cycles, that is, if it is a directed acyclic graph (DAG). Any DAG has at least one topological ordering, and algorithms are known for constructing a topological ordering of any DAG in linear time.*/ import java.util.InputMismatchException; import java.util.Scanner; import java.util.Stack; public class DigraphTopologicalSortingDFS { private Stack stack; public DigraphTopologicalSortingDFS() { stack = new Stack(); } public int[] topological(int adjacency_matrix[][], int source) throws NullPointerException { int number_of_nodes = adjacency_matrix[source].length - 1; int[] topological_sort = new int[number_of_nodes + 1]; int pos = 1; int j; int visited[] = new int[number_of_nodes + 1]; int element = source; int i = source; visited[source] = 1; stack.push(source); while (!stack.isEmpty()) { element = stack.peek(); while (i <= number_of_nodes) { if (adjacency_matrix[element][i] == 1 && visited[i] == 1) { if (stack.contains(i)) { System.out.println("TOPOLOGICAL SORT NOT POSSIBLE"); return null; } } if (adjacency_matrix[element][i] == 1 && visited[i] == 0) { stack.push(i); visited[i] = 1; element = i; i = 1; continue; } i++; } j = stack.pop(); topological_sort[pos++] = j; i = ++j; } return topological_sort; } public static void main(String... arg) { int number_no_nodes, source; Scanner scanner = null; int topological_sort[] = null; try { System.out.println("Enter the number of nodes in the graph"); scanner = new Scanner(System.in); number_no_nodes = scanner.nextInt(); int adjacency_matrix[][] = new int[number_no_nodes + 1][number_no_nodes + 1]; System.out.println("Enter the adjacency matrix"); for (int i = 1; i <= number_no_nodes; i++) for (int j = 1; j <= number_no_nodes; j++) adjacency_matrix[i][j] = scanner.nextInt(); System.out.println("Enter the source for the graph"); source = scanner.nextInt(); System.out .println("The Topological sort for the graph is given by "); DigraphTopologicalSortingDFS toposort = new DigraphTopologicalSortingDFS(); topological_sort = toposort.topological(adjacency_matrix, source); for (int i = topological_sort.length - 1; i > 0; i--) { if (topological_sort[i] != 0) System.out.print(topological_sort[i] + "\t"); } } catch (InputMismatchException inputMismatch) { System.out.println("Wrong Input format"); } catch (NullPointerException nullPointer) { } scanner.close(); } } /* Enter the number of nodes in the graph 6 Enter the adjacency matrix 0 1 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 1 0 0 Enter the source for the graph 1 The Topological sort for the graph is given by TOPOLOGICAL SORT NOT POSSIBLE Enter the number of nodes in the graph 6 Enter the adjacency matrix 0 1 0 0 0 1 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 Enter the source for the graph 1 The Topological sort for the graph is given by 1 2 4 5 6 3