/************************************************************************* * Compilation: javac TrieSET.java * Execution: java TrieSET < words.txt * Dependencies: StdIn.java * * An set for extended ASCII strings, implemented using a 256-way trie. * * Sample client reads in a list of words from standard input and * prints out each word, removing any duplicates. * *************************************************************************/ import java.util.Iterator; import edu.princeton.cs.introcs.StdIn; import edu.princeton.cs.introcs.StdOut; /** * The TrieSET class represents an ordered set of strings over * the extended ASCII alphabet. * It supports the usual add , contains , and delete * methods. It also provides character-based methods for finding the string * in the set that is the longest prefix of a given prefix, * finding all strings in the set that start with a given prefix, * and finding all strings in the set that match a given pattern. * * This implementation uses a 256-way trie. * The add , contains , delete , and * longest prefix methods take time proportional to the length * of the key (in the worst case). Construction takes constant time. * * For additional documentation, see * Section 5.2 of * Algorithms in Java, 4th Edition by Robert Sedgewick and Kevin Wayne. * * @author Robert Sedgewick * @author Kevin Wayne */ public class TrieSET implements Iterable { private static final int R = 256; // extended ASCII private Node root; // root of trie private int N; // number of keys in trie // R-way trie node private static class Node { private Node[] next = new Node[R]; private boolean isString; } /** * Initializes an empty set of strings. */ public TrieSET() { } /** * Does the set contain the given key? * @param key the key * @return true if the set contains key and * false otherwise * @throws NullPointerException if key is null */ public boolean contains(String key) { Node x = get(root, key, 0); if (x == null) return false; return x.isString; } private Node get(Node x, String key, int d) { if (x == null) return null; if (d == key.length()) return x; char c = key.charAt(d); return get(x.next[c], key, d+1); } /** * Adds the key to the set if it is not already present. * @param key the key to add * @throws NullPointerException if key is null */ public void add(String key) { root = add(root, key, 0); } private Node add(Node x, String key, int d) { if (x == null) x = new Node(); if (d == key.length()) { if (!x.isString) N++; x.isString = true; } else { char c = key.charAt(d); x.next[c] = add(x.next[c], key, d+1); } return x; } /** * Returns the number of strings in the set. * @return the number of strings in the set */ public int size() { return N; } /** * Is the set empty? * @return true if the set is empty, and false otherwise */ public boolean isEmpty() { return size() == 0; } /** * Returns all of the keys in the set, as an iterator. * To iterate over all of the keys in a set named set , use the * foreach notation: for (Key key : set) . * @return an iterator to all of the keys in the set */ public Iterator iterator() { return keysWithPrefix("").iterator(); } /** * Returns all of the keys in the set that start with prefix . * @param prefix the prefix * @return all of the keys in the set that start with prefix , * as an iterable */ public Iterable keysWithPrefix(String prefix) { Queue results = new Queue(); Node x = get(root, prefix, 0); collect(x, new StringBuilder(prefix), results); return results; } private void collect(Node x, StringBuilder prefix, Queue results) { if (x == null) return; if (x.isString) results.enqueue(prefix.toString()); for (char c = 0; c < R; c++) { prefix.append(c); collect(x.next[c], prefix, results); prefix.deleteCharAt(prefix.length() - 1); } } /** * Returns all of the keys in the set that match pattern , * where . symbol is treated as a wildcard character. * @param pattern the pattern * @return all of the keys in the set that match pattern , * as an iterable, where . is treated as a wildcard character. */ public Iterable keysThatMatch(String pattern) { Queue results = new Queue(); StringBuilder prefix = new StringBuilder(); collect(root, prefix, pattern, results); return results; } private void collect(Node x, StringBuilder prefix, String pattern, Queue results) { if (x == null) return; int d = prefix.length(); if (d == pattern.length() && x.isString) results.enqueue(prefix.toString()); if (d == pattern.length()) return; char c = pattern.charAt(d); if (c == '.') { for (char ch = 0; ch < R; ch++) { prefix.append(ch); collect(x.next[ch], prefix, pattern, results); prefix.deleteCharAt(prefix.length() - 1); } } else { prefix.append(c); collect(x.next[c], prefix, pattern, results); prefix.deleteCharAt(prefix.length() - 1); } } /** * Returns the string in the set that is the longest prefix of query , * or null , if no such string. * @param query the query string * @throws NullPointerException if query is null * @return the string in the set that is the longest prefix of query , * or null if no such string */ public String longestPrefixOf(String query) { int length = longestPrefixOf(root, query, 0, -1); if (length == -1) return null; return query.substring(0, length); } // returns the length of the longest string key in the subtrie // rooted at x that is a prefix of the query string, // assuming the first d character match and we have already // found a prefix match of length length private int longestPrefixOf(Node x, String query, int d, int length) { if (x == null) return length; if (x.isString) length = d; if (d == query.length()) return length; char c = query.charAt(d); return longestPrefixOf(x.next[c], query, d+1, length); } /** * Removes the key from the set if the key is present. * @param key the key * @throws NullPointerException if key is null */ public void delete(String key) { root = delete(root, key, 0); } private Node delete(Node x, String key, int d) { if (x == null) return null; if (d == key.length()) { if (x.isString) N--; x.isString = false; } else { char c = key.charAt(d); x.next[c] = delete(x.next[c], key, d+1); } // remove subtrie rooted at x if it is completely empty if (x.isString) return x; for (int c = 0; c < R; c++) if (x.next[c] != null) return x; return null; } /** * Unit tests the TrieSET data type. */ public static void main(String[] args) { TrieSET set = new TrieSET(); while (!StdIn.isEmpty()) { String key = StdIn.readString(); set.add(key); } // print results if (set.size() < 100) { StdOut.println("keys(\"\"):"); for (String key : set) { StdOut.println(key); } StdOut.println(); } StdOut.println("longestPrefixOf(\"shellsort\"):"); StdOut.println(set.longestPrefixOf("shellsort")); StdOut.println(); StdOut.println("longestPrefixOf(\"xshellsort\"):"); StdOut.println(set.longestPrefixOf("xshellsort")); StdOut.println(); StdOut.println("keysWithPrefix(\"shor\"):"); for (String s : set.keysWithPrefix("shor")) StdOut.println(s); StdOut.println(); StdOut.println("keysWithPrefix(\"shortening\"):"); for (String s : set.keysWithPrefix("shortening")) StdOut.println(s); StdOut.println(); StdOut.println("keysThatMatch(\".he.l.\"):"); for (String s : set.keysThatMatch(".he.l.")) StdOut.println(s); } }