import edu.princeton.cs.introcs.In; import edu.princeton.cs.introcs.StdOut; /************************************************************************* * Compilation: javac DirectedCycle.java * Execution: java DirectedCycle < input.txt * Dependencies: Digraph.java Stack.java StdOut.java In.java * Data files: http://algs4.cs.princeton.edu/42directed/tinyDG.txt * http://algs4.cs.princeton.edu/42directed/tinyDAG.txt * * Finds a directed cycle in a digraph. * Runs in O(E + V) time. * * % java DirectedCycle tinyDG.txt * Cycle: 3 5 4 3 * * % java DirectedCycle tinyDAG.txt * No cycle * *************************************************************************/ /** * The DirectedCycle class represents a data type for * determining whether a digraph has a directed cycle. * The hasCycle operation determines whether the digraph has * a directed cycle and, and of so, the cycle operation * returns one. * * This implementation uses depth-first search. * The constructor takes time proportional to V + E * (in the worst case), * where V is the number of vertices and E is the number of edges. * Afterwards, the hasCycle operation takes constant time; * the cycle operation takes time proportional * to the length of the cycle. * * See {@link Topological} to compute a topological order if the * digraph is acyclic. * * For additional documentation, see Section 4.2 of * Algorithms, 4th Edition by Robert Sedgewick and Kevin Wayne. * * @author Robert Sedgewick * @author Kevin Wayne */ public class DirectedCycle { private boolean[] marked; // marked[v] = has vertex v been marked? private int[] edgeTo; // edgeTo[v] = previous vertex on path to v private boolean[] onStack; // onStack[v] = is vertex on the stack? private Stack cycle; // directed cycle (or null if no such cycle) /** * Determines whether the digraph G has a directed cycle and, if so, * finds such a cycle. * @param G the digraph */ public DirectedCycle(Digraph G) { marked = new boolean[G.V()]; onStack = new boolean[G.V()]; edgeTo = new int[G.V()]; for (int v = 0; v < G.V(); v++) if (!marked[v]) dfs(G, v); } // check that algorithm computes either the topological order or finds a directed cycle private void dfs(Digraph G, int v) { onStack[v] = true; marked[v] = true; for (int w : G.adj(v)) { // short circuit if directed cycle found if (cycle != null) return; //found new vertex, so recur else if (!marked[w]) { edgeTo[w] = v; dfs(G, w); } // trace back directed cycle else if (onStack[w]) { cycle = new Stack(); for (int x = v; x != w; x = edgeTo[x]) { cycle.push(x); } cycle.push(w); cycle.push(v); } } onStack[v] = false; } /** * Does the digraph have a directed cycle? * @return true if the digraph has a directed cycle, false otherwise */ public boolean hasCycle() { return cycle != null; } /** * Returns a directed cycle if the digraph has a directed cycle, and null otherwise. * @return a directed cycle (as an iterable) if the digraph has a directed cycle, * and null otherwise */ public Iterable cycle() { return cycle; } // certify that digraph is either acyclic or has a directed cycle private boolean check(Digraph G) { if (hasCycle()) { // verify cycle int first = -1, last = -1; for (int v : cycle()) { if (first == -1) first = v; last = v; } if (first != last) { System.err.printf("cycle begins with %d and ends with %d\n", first, last); return false; } } return true; } /** * Unit tests the DirectedCycle data type. */ public static void main(String[] args) { In in = new In(args[0]); Digraph G = new Digraph(in); DirectedCycle finder = new DirectedCycle(G); if (finder.hasCycle()) { StdOut.print("Cycle: "); for (int v : finder.cycle()) { StdOut.print(v + " "); } StdOut.println(); } else { StdOut.println("No cycle"); } } }