/*
 * C program to find the sum of all digits present in the string
 */
#include <stdio.h>
void main()
{
    char string[80];
    int count, nc = 0, sum = 0;
    printf("Enter the string containing both digits and alphabet \n");
    scanf("%s", string);
    for (count = 0; string[count] != '\0'; count++)
        {
            if ((string[count] >= '0') && (string[count] <= '9'))
                {
                    nc += 1;
                    sum += (string[count] - '0');
                }
        }
    printf("NO. of Digits in the string = %d\n", nc);
    printf("Sum of all digits = %d\n", sum);
}
/*
*OUTPUT:
Enter the string containing both digits and alphabet
hello100
NO. of Digits in the string = 3
Sum of all digits = 1
*/