/* Decimal to Octal , Hexa , Binary - Using recursion write a program to find octal , binary and hexadecimal equivalent of the natural (decimal) number entered by the user */

#include  <stdio.h>
#include  <conio.h>

void  octal(int  n)
{
    if(n!=0)
        {
            octal(n/8) ;
            printf("%d", n%8) ;
        }
}

void  binary(int  n)
{
    if(n!=0)
        {
            binary(n/2) ;
            printf("%d", n%2) ;
        }
}

void  hexa(int  n)
{
    if(n!=0)
        {
            hexa(n/16) ;
            if(n%16 < 10)
                printf("%d", n%16) ;
            else
                printf("%c", n%16 + 55) ;
        }
}

void main()
{
    int  n ;
    clrscr() ;
    printf("Enter a natural number: ") ;
    scanf("%d", &n) ;
    printf("Equivalent octal, binary and hexadecimal numbers are as shown: \n") ;
    octal(n) ;
    printf("\n") ;
    binary(n) ;
    printf("\n") ;
    hexa(n) ;
    printf("\n") ;
    getch() ;
}

/*
Output:

Enter a natural number: 43
Equivalent octal, binary and hexadecimal numbers are as shown:
53
101011
2B
*/