/* * C++ Program to Count Inversion in an Array */ #include #include using namespace std; int mSort(int arr[], int temp[], int left, int right); int merge(int arr[], int temp[], int left, int mid, int right); /* * calls mSort */ int mergeSort(int arr[], int array_size) { int *temp = new int [array_size]; return mSort(arr, temp, 0, array_size - 1); } /* * sorts the input array and returns the number of inversions in the array. */ int mSort(int arr[], int temp[], int left, int right) { int mid, inv_count = 0; if (right > left) { mid = (right + left)/2; inv_count = mSort(arr, temp, left, mid); inv_count += mSort(arr, temp, mid+1, right); inv_count += merge(arr, temp, left, mid+1, right); } return inv_count; } /* * merges two sorted arrays and returns inversion count in the arrays. */ int merge(int arr[], int temp[], int left, int mid, int right) { int i, j, k; int inv_count = 0; i = left; j = mid; k = left; while ((i <= mid - 1) && (j <= right)) { if (arr[i] <= arr[j]) { temp[k++] = arr[i++]; } else { temp[k++] = arr[j++]; inv_count = inv_count + (mid - i); } } while (i <= mid - 1) temp[k++] = arr[i++]; while (j <= right) temp[k++] = arr[j++]; for (i = left; i <= right; i++) arr[i] = temp[i]; return inv_count; } /* * Main */ int main() { int arr[] = {1, 20, 6, 4, 5}; cout<<"Number of inversions are "<