35 lines
1.2 KiB
Ruby
35 lines
1.2 KiB
Ruby
|
# You are a product manager and currently leading a team to develop a new product.
|
||
|
# Unfortunately, the latest version of your product fails the quality check.
|
||
|
# Since each version is developed based on the previous version,
|
||
|
# all the versions after a bad version are also bad.
|
||
|
#
|
||
|
# Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one,
|
||
|
# which causes all the following ones to be bad.
|
||
|
#
|
||
|
# You are given an API bool is_bad_version?(version) which will return whether version is bad.
|
||
|
# Implement a function to find the first bad version.
|
||
|
# You should minimize the number of calls to the API.
|
||
|
# The is_bad_version? API is already defined for you.
|
||
|
|
||
|
# @param {Integer} version
|
||
|
# @return {boolean} whether the version is bad
|
||
|
# def is_bad_version?(version)
|
||
|
# version >= 69 ? true : false
|
||
|
# end
|
||
|
|
||
|
# @param {Integer[]} versions
|
||
|
# @return {Integer}
|
||
|
|
||
|
def first_bad_version(versions)
|
||
|
# binary search
|
||
|
midpoint = (versions.length - 1) / 2
|
||
|
middle_version = versions[midpoint]
|
||
|
return 1 if middle_version == versions.first
|
||
|
|
||
|
if is_bad_version?(middle_version)
|
||
|
first_bad_version(versions[0..midpoint])
|
||
|
else
|
||
|
midpoint + first_bad_version(versions[midpoint..-1])
|
||
|
end
|
||
|
end
|