54 lines
1.7 KiB
C
54 lines
1.7 KiB
C
|
/* Structure - Cricket
|
||
|
|
Define a structure called cricket that will describe the following info
|
||
|
|
1)player name 2)team name 3)no of matches played 4)batting average
|
||
|
|
Declare an array player with 50 elements. Write a program to read information about all 50 players. Sort the information on their batting average and print the results */
|
||
|
|
|
||
|
|
|
||
|
|
#include <stdio.h>
|
||
|
|
#include <conio.h>
|
||
|
|
|
||
|
|
void main()
|
||
|
|
{
|
||
|
|
struct cricket
|
||
|
|
{
|
||
|
|
char pname[20] ;
|
||
|
|
char tname[20] ;
|
||
|
|
int np ;
|
||
|
|
float avg ;
|
||
|
|
};
|
||
|
|
/* Some compilers do not allow float member in a structure. In that case make avg to be of data type int */
|
||
|
|
struct cricket player[50], temp ;
|
||
|
|
int i, j ;
|
||
|
|
clrscr();
|
||
|
|
printf("Enter player name , team name , number of matches played and batting average for 50 players:\n") ;
|
||
|
|
for(i=0 ; i<50 ; i++)
|
||
|
|
scanf("%s %s %d %f", player[i].pname, player[i].tname, &player[i].np, &player[i].avg) ;
|
||
|
|
for(i=0 ; i<50-1 ; i++)
|
||
|
|
for(j=0 ; j<50-1-i ; j++)
|
||
|
|
if(player[j].avg < player[j+1].avg )
|
||
|
|
{
|
||
|
|
temp=player[j] ;
|
||
|
|
player[j]=player[j+1] ;
|
||
|
|
player[j+1]=temp ;
|
||
|
|
}
|
||
|
|
printf("\nList in descending order of batting average is as shown:\n") ;
|
||
|
|
for(i=0 ; i<50 ; i++)
|
||
|
|
printf("%s %s %d %f \n", player[i].pname, player[i].tname, player[i].np, player[i].avg) ;
|
||
|
|
getch();
|
||
|
|
}
|
||
|
|
|
||
|
|
/*
|
||
|
|
The following output is shown for 3 players only:
|
||
|
|
|
||
|
|
Enter player name , team name , number of matches played and batting average for 50 players:
|
||
|
|
Jack Australia 202 67.5
|
||
|
|
Sachin India 210 82.75
|
||
|
|
Tim U.K. 205 76.25
|
||
|
|
|
||
|
|
List in descending order of batting average is as shown:
|
||
|
|
Sachin India 210 82.750000
|
||
|
|
Tim U.K. 205 76.250000
|
||
|
|
Jack Australia 202 67.500000
|
||
|
|
*/
|
||
|
|
|