programming-examples/c/String/C Program to Concatenate two Strings Lexically.c

115 lines
3.4 KiB
C
Raw Normal View History

2019-11-15 12:59:38 +01:00
/*
* C Program to Concatenate the given two Strings Lexically
*/
#include <string.h>
#include <stdio.h>
void sort(char *p);
void main()
{
char string1[100], string2[100];
int i, len, j;
printf("\nEnter a string : ");
scanf("%[^\n]s", string1);
printf("\nEnter another string to concat : ");
scanf(" %[^\n]s", string2);
len = strlen(string1);
string1[len] = ' ';
for(i = 0, j = len + 1; i < strlen(string2); i++, j++)
string1[j] = string2[i];
string1[j]='\0';
sort(string1);
}
/* Sorting to make concatenation lexical */
void sort(char *p)
{
char temp[100];
char a[100][100];
int t1, i, j = 0, k = 0, l = strlen(p), x = 0, y = 0, z = 0, count, l1, l2;
for (i = 0; i < l; i++)
{
if (p[i] != ' ')
{
a[k][j++] = p[i];
}
else
{
a[k][j] = '\0';
k++;
j = 0;
}
}
t1 = k;
k = 0;
for (i = 0; i < t1; i++)
{
for (j = i + 1; j <= t1; j++)
{
l1 = strlen(a[i]);
l2 = strlen(a[j]);
if (l1 > l2)
count = l1;
else
count = l2;
x = 0, y = 0;
while ((x < count) || (y < count))
{
if (a[i][x] == a[j][y])
{
x++;
y++;
continue;
}
else if (a[i][x] < a[j][y]) break;
else if (a[i][x] > a[j][y])
{
for (z = 0; z < l2; z++)
{
temp[z] = a[j][z];
a[j][z] = '\0';
}
temp[z] = '\0';
for (z = 0; z < l1; z++)
{
a[j][z] = a[i][z];
a[i][z] = '\0';
}
a[j][z] = '\0';
for (z = 0; z < strlen(temp); z++)
{
a[i][z] = temp[z];
}
break;
}
}
}
}
for (i = 0; i < l; i++)
p[i] = '\0';
k = 0;
j = 0;
for (i = 0; i < l; i++)
{
if (a[k][j] != '\0')
{
p[i] = a[k][j++];
}
else
{
k++;
j = 0;
p[i] = ' ';
}
}
puts(p);
}
/*
*OUTPUT:
Enter a string : hello this
Enter another string to concat : is sanfoundry
hello is sanfoundry this
*/