156 lines
4.6 KiB
Java
156 lines
4.6 KiB
Java
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import edu.princeton.cs.introcs.In;
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import edu.princeton.cs.introcs.StdOut;
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/*************************************************************************
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* Compilation: javac DirectedCycle.java
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* Execution: java DirectedCycle < input.txt
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* Dependencies: Digraph.java Stack.java StdOut.java In.java
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* Data files: http://algs4.cs.princeton.edu/42directed/tinyDG.txt
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* http://algs4.cs.princeton.edu/42directed/tinyDAG.txt
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*
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* Finds a directed cycle in a digraph.
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* Runs in O(E + V) time.
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*
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* % java DirectedCycle tinyDG.txt
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* Cycle: 3 5 4 3
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*
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* % java DirectedCycle tinyDAG.txt
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* No cycle
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*
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*************************************************************************/
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/**
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* The DirectedCycle class represents a data type for
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* determining whether a digraph has a directed cycle.
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* The hasCycle operation determines whether the digraph has
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* a directed cycle and, and of so, the cycle operation
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* returns one.
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*
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* This implementation uses depth-first search.
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* The constructor takes time proportional to V + E
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* (in the worst case),
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* where V is the number of vertices and E is the number of edges.
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* Afterwards, the hasCycle operation takes constant time;
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* the cycle operation takes time proportional
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* to the length of the cycle.
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*
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* See {@link Topological} to compute a topological order if the
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* digraph is acyclic.
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*
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* For additional documentation, see <a href="/algs4/42digraph">Section 4.2</a> of
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* Algorithms, 4th Edition by Robert Sedgewick and Kevin Wayne.
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*
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* @author Robert Sedgewick
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* @author Kevin Wayne
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*/
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public class DirectedCycle {
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private boolean[] marked; // marked[v] = has vertex v been marked?
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private int[] edgeTo; // edgeTo[v] = previous vertex on path to v
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private boolean[] onStack; // onStack[v] = is vertex on the stack?
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private Stack<Integer> cycle; // directed cycle (or null if no such cycle)
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/**
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* Determines whether the digraph G has a directed cycle and, if so,
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* finds such a cycle.
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* @param G the digraph
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*/
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public DirectedCycle(Digraph G) {
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marked = new boolean[G.V()];
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onStack = new boolean[G.V()];
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edgeTo = new int[G.V()];
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for (int v = 0; v < G.V(); v++)
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if (!marked[v]) dfs(G, v);
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}
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// check that algorithm computes either the topological order or finds a directed cycle
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private void dfs(Digraph G, int v) {
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onStack[v] = true;
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marked[v] = true;
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for (int w : G.adj(v)) {
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// short circuit if directed cycle found
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if (cycle != null) return;
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//found new vertex, so recur
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else if (!marked[w]) {
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edgeTo[w] = v;
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dfs(G, w);
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}
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// trace back directed cycle
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else if (onStack[w]) {
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cycle = new Stack<Integer>();
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for (int x = v; x != w; x = edgeTo[x]) {
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cycle.push(x);
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}
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cycle.push(w);
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cycle.push(v);
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}
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}
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onStack[v] = false;
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}
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/**
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* Does the digraph have a directed cycle?
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* @return true if the digraph has a directed cycle, false otherwise
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*/
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public boolean hasCycle() {
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return cycle != null;
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}
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/**
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* Returns a directed cycle if the digraph has a directed cycle, and null otherwise.
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* @return a directed cycle (as an iterable) if the digraph has a directed cycle,
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* and null otherwise
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*/
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public Iterable<Integer> cycle() {
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return cycle;
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}
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// certify that digraph is either acyclic or has a directed cycle
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private boolean check(Digraph G) {
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if (hasCycle()) {
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// verify cycle
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int first = -1, last = -1;
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for (int v : cycle()) {
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if (first == -1) first = v;
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last = v;
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}
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if (first != last) {
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System.err.printf("cycle begins with %d and ends with %d\n", first, last);
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return false;
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}
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}
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return true;
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}
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/**
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* Unit tests the DirectedCycle data type.
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*/
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public static void main(String[] args) {
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In in = new In(args[0]);
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Digraph G = new Digraph(in);
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DirectedCycle finder = new DirectedCycle(G);
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if (finder.hasCycle()) {
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StdOut.print("Cycle: ");
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for (int v : finder.cycle()) {
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StdOut.print(v + " ");
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}
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StdOut.println();
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}
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else {
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StdOut.println("No cycle");
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}
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}
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}
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