programming-examples/c-sharp/Arrays/C# Sharp to print all unique elements in an array.cs

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2019-11-15 12:59:38 +01:00
using System;
public class Exercise6
{
public static void Main()
{
int n,ctr=0;
int[] arr1 = new int[100];
int i, j, k;
Console.Write("\n\nPrint all unique elements of an array:\n");
Console.Write("------------------------------------------\n");
Console.Write("Input the number of elements to be stored in the array :");
n = Convert.ToInt32(Console.ReadLine());
Console.Write("Input {0} elements in the array :\n",n);
for(i=0; i<n; i++)
{
Console.Write("element - {0} : ",i);
arr1[i] = Convert.ToInt32(Console.ReadLine());
}
/*Checking duplicate elements in the array */
Console.Write("\nThe unique elements found in the array are : \n");
for(i=0; i<n; i++)
{
ctr=0;
/*Check duplicate bifore the current position and
increase counter by 1 if found.*/
for(j=0; j<i-1; j++)
{
/*Increment the counter when the seaarch value is duplicate.*/
if(arr1[i]==arr1[j])
{
ctr++;
}
}
/*Check duplicate after the current position and
increase counter by 1 if found.*/
for(k=i+1; k<n; k++)
{
/*Increment the counter when the seaarch value is duplicate.*/
if(arr1[i]==arr1[k])
{
ctr++;
}
}
/*Print the value of the current position of the array as unique value
when counter remain contains its initial value.*/
if(ctr==0)
{
Console.Write("{0} ",arr1[i]);
}
}
Console.Write("\n\n");
}
}