12 lines
374 B
MySQL
12 lines
374 B
MySQL
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/*Write a query to identify all the employees who earn more than the average and who work in any of the IT departments.
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*/
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SELECT last_name
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FROM employees
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WHERE department_id IN
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(SELECT department_id
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FROM departments
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WHERE department_name LIKE 'IT%')
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AND salary >
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(SELECT avg(salary)
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FROM employees);
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