11 lines
388 B
MySQL
11 lines
388 B
MySQL
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/*Write a query to display the employee number, name( first name and last name ) and job title for all employees whose salary
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is more than any average salary of any department.
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*/
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SELECT employee_id, first_name, last_name, job_id
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FROM employees
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WHERE salary > ALL
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( SELECT AVG(salary)
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FROM employees
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GROUP BY department_id
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);
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