/*Write a query to display the department id and the total salary for those departments which contains at least one salaried
 employee.

*/

    SELECT departments.department_id, result1.total_amt   
    FROM departments,    
    ( SELECT employees.department_id, SUM(employees.salary) total_amt    
    FROM employees    
    GROUP BY department_id) result1   
    WHERE result1.department_id = departments.department_id;