/* Sum of series - Program to find sum of series 1 + 1/2 + 1/3 + ....... + 1/n */

#include  <stdio.h>
#include  <conio.h>

void main()
{
    int  n ;
    float  i, s=0 ;
    clrscr() ;
    printf("Enter n: ") ;
    scanf("%d", &n) ;
    for(i=1 ; i<=n ; i++)
        s=s+1/i ;
    /* i has to be float in the above expression. If i is int then s is always 1.000000 since 1/i will be 0 for all i>1  */
    printf("Sum of the required series is %f", s) ;
    getch() ;
}

/*
Output :

Enter n: 3
Sum of the required series is 1.833333
*/

